When 47.2 J of heat is added to 14.0 g of a liquid, its temperature rises by 1.78 ∘C.?
回答 (1)
2020-08-26 3:51 pm
Suppose it is asking for the specific heat capacity of the liquid.
q = m c ΔT
Then, c = q / (m ΔT)
Specific heat capacity, c = (47.2 J) / [(14.0 g) × (1.78 °C)] = 1.89 J/g•°C
q = m c ΔT
Then, c = q / (m ΔT)
Specific heat capacity, c = (47.2 J) / [(14.0 g) × (1.78 °C)] = 1.89 J/g•°C
收錄日期: 2021-04-24 07:59:03
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