Find the maximum and minimum values for P if any, Let P(t)=100+20 cos6t,0≤t≤π/2.?
回答 (1)
2020-08-25 7:41 pm
✔ 最佳答案
0 ≤ t ≤ π/20 ≤ 6t ≤ 3π
-1 ≤ cos(6t) ≤ 1
-20 ≤ 20 cos(6t) ≤ 20
100 - 20 ≤ 100 + 20 cos(6t) ≤ 100 + 20
80 ≤ P ≤ 120
The minimum value for P = 80
The maximum value for P = 120
收錄日期: 2021-04-24 07:57:52
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