Evaluate the the following limit.?
回答 (2)
2020-08-18 7:59 pm
10^n/(n+1)8^(2n+1)=2^n*5^n/(n+1) 2^(6n+3)= 2^(-5n-3)*5^n/(n+1)
2^(-5n) goes to 0 faster than 5^n. Therefore we expect the limit to be 0.
2^(-5n) goes to 0 faster than 5^n. Therefore we expect the limit to be 0.
收錄日期: 2021-04-24 08:04:49
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