Given that 0 < x < Pi/2 and cos(x) = sin(Pi/6), find the value of x.
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2020-08-17 8:18 pm
回答 (3)
2020-08-17 8:44 pm
cos(x) = sin(π/6)
sin[(π/2) - x] = sin(π/6)
(π/2) - x = π/6
x = (π/2) - (π/6)
x = π/3
sin[(π/2) - x] = sin(π/6)
(π/2) - x = π/6
x = (π/2) - (π/6)
x = π/3
2020-08-18 6:42 pm
sinθ = cos(π/2 - θ)
so, sin(π/6) = cos(π/2 - π/6)
i.e. cos(π/3)
Hence, x = π/3....for 0 < x < π/2
:)>
so, sin(π/6) = cos(π/2 - π/6)
i.e. cos(π/3)
Hence, x = π/3....for 0 < x < π/2
:)>
2020-08-17 8:41 pm
cosx = sin(pi/6)
cosx = cos(pi/2 - pi/6)
cosx = cos(pi/3)
x = pi/3
cosx = cos(pi/2 - pi/6)
cosx = cos(pi/3)
x = pi/3
收錄日期: 2021-04-24 08:02:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200817121808AA1i0oK