Need help with Maths - Complementary angles question!?

2020-08-17 8:18 pm

Given that 0 < x < Pi/2 and cos(x) = sin(Pi/6), find the value of x.
Thanks!

回答 (3)

2020-08-17 8:44 pm

cos(x) = sin(π/6)
sin[(π/2) - x] = sin(π/6)
(π/2) - x = π/6
x = (π/2) - (π/6)
x = π/3

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2020-08-18 6:42 pm

sinθ = cos(π/2 - θ)

so, sin(π/6) = cos(π/2 - π/6)

i.e. cos(π/3)

Hence, x = π/3....for 0 < x < π/2

:)>

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2020-08-17 8:41 pm

cosx = sin(pi/6)
cosx = cos(pi/2 - pi/6)
cosx = cos(pi/3)
x = pi/3

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