Find the molarity of a copper (II) ion solution (Cu2+) ?
2020-08-17 5:42 pm
if it requires 30.8 mL of 0.267 M S2– solution to reach an equivalence point with 35.6 mL of the copper (II) ion solution.
回答 (1)
2020-08-17 6:34 pm
Equation for the reaction:
Cu²⁺ + S²⁻ → CuS
1 mol Cu²⁺ reacts with 1 mol S²⁻.
Moles of S²⁻ reacted = (0.267 mol/L) × (30.8/1000 L) = 0.008224 mol
Moles of Cu²⁺ reacted = 0.008224 mol
Molarity of Cu²⁺ = (0.00824 mol) / (35.6/1000 L) = 0.231 L = 23.1 mL
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OR:
(0.267 mol S²⁻ / 1000 mL S²⁻ solution) × (30.8 mL S²⁻ solution) × (1 mol Cu²⁺ / 1 mol S²⁻) / (35.6/1000 L Cu²⁺ solution)
= 0.231 M Cu²⁺ solution
Cu²⁺ + S²⁻ → CuS
1 mol Cu²⁺ reacts with 1 mol S²⁻.
Moles of S²⁻ reacted = (0.267 mol/L) × (30.8/1000 L) = 0.008224 mol
Moles of Cu²⁺ reacted = 0.008224 mol
Molarity of Cu²⁺ = (0.00824 mol) / (35.6/1000 L) = 0.231 L = 23.1 mL
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OR:
(0.267 mol S²⁻ / 1000 mL S²⁻ solution) × (30.8 mL S²⁻ solution) × (1 mol Cu²⁺ / 1 mol S²⁻) / (35.6/1000 L Cu²⁺ solution)
= 0.231 M Cu²⁺ solution
收錄日期: 2021-04-24 07:56:13
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