maths differentiation ?

2020-08-15 1:13 pm
Determine the first and second differential coefficients of the expression:
y = 2/√x   +  4sinx – 3 lnx

回答 (2)

2020-08-15 7:34 pm
The answer is as follows:
2020-08-15 7:02 pm
y = 2/√x   +  4sinx – 3 lnx, y= 2 x^(-1/2) + 4 sin x - 3 cos x, y'= -3 x^(-3/2) + 4 cos x -3/x, y''= 15/2 x^(-5/2)-4 sin x + 3 x^2


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