Find the fourteenth term of the geometric sequences 18/,1/4,1/2...?
回答 (3)
2020-08-14 12:56 am
The first term, a = 1/8 (NOT "18/")
The common ratio, r = (1/4)/(1/8) = (1/2)/(1/4) = 2
The 14th term
= a rⁿ⁻¹
= (1/8) 2¹⁴⁻¹
= (1/8) 2¹³
= 1024
The common ratio, r = (1/4)/(1/8) = (1/2)/(1/4) = 2
The 14th term
= a rⁿ⁻¹
= (1/8) 2¹⁴⁻¹
= (1/8) 2¹³
= 1024
2020-08-14 12:53 am
a(n) = (1/8)(2^(n-1)), n = 1,2,3,4...
a(14) = (1/8)(2^13) = 1024
a(14) = (1/8)(2^13) = 1024
2020-08-14 6:56 am
a_n = 2^n/16
a_14 = 2^14/16 = 1024
a_14 = 2^14/16 = 1024
收錄日期: 2021-04-18 18:36:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200813164302AA9EZvc