How many moles of gas occupy 98 L at a pressure of 2.8 atmospheres and a temperature of 292 K?
回答 (3)
2020-08-13 12:21 am
Volume, V = 98 L
Pressure, P = 2.8 atm
Temperature, T = 292 K
Gas constant, R = 0.08206 L atm / (mol K)
Gas law: PV = nRT
Then, n = PV/(RT)
No. of moles, n = 2.8 × 98 / (0.08206 × 292) mol = 11.5 mol
Pressure, P = 2.8 atm
Temperature, T = 292 K
Gas constant, R = 0.08206 L atm / (mol K)
Gas law: PV = nRT
Then, n = PV/(RT)
No. of moles, n = 2.8 × 98 / (0.08206 × 292) mol = 11.5 mol
2020-08-12 11:34 pm
Use the ideal gas equation PV=nRT
2020-08-13 2:19 am
We will use the equation PV=nRT
2.8×98=n×0.082×292
n=11.46 moles of gas.
2.8×98=n×0.082×292
n=11.46 moles of gas.
收錄日期: 2021-04-18 18:37:01
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