How many moles of gas occupy 98 L at a pressure of 2.8 atmospheres and a temperature of 292 K?

Volume, V = 98 L
Pressure, P = 2.8 atm
Temperature, T = 292 K
Gas constant, R = 0.08206 L atm / (mol K)

Gas law: PV = nRT
Then, n = PV/(RT)

No. of moles, n = 2.8 × 98 / (0.08206 × 292) mol = 11.5 mol

Use the ideal gas equation PV=nRT

We will use the equation PV=nRT

2.8×98=n×0.082×292

n=11.46 moles of gas.