The solubility of PbCO3(s) in water at a certain temperature is 3.2 × 10–7 mol/L. Calculate the valueof Ksp for BaCO3(s) at this temperature?
回答 (1)
2020-08-11 6:27 pm
PbCO₃(s) ⇌ Pb²⁺(aq) + CO₃²⁻(aq) Ksp = ?
Eqm: 3.2 × 10⁻⁷ M 3.2 × 10⁻⁷ M
At equilibrium: Ksp
= [Pb²⁺] [CO₃²⁻]
= (3.2 × 10⁻⁷)²
= 1.0 × 10⁻¹³
Eqm: 3.2 × 10⁻⁷ M 3.2 × 10⁻⁷ M
At equilibrium: Ksp
= [Pb²⁺] [CO₃²⁻]
= (3.2 × 10⁻⁷)²
= 1.0 × 10⁻¹³
收錄日期: 2021-04-24 07:55:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200811091047AAVLOIa