Calculate the molarity of ammonia (NH3) in a cleaner.?

Given : volume of cleaner sample = 25.00 mL

concentration of HCl added = 0.1000 M

volume of HCl added = 25.00 mL

total moles of HCl added = (concentration of HCl added) * (volume of HCl added)

total moles of HCl added = (0.1000 M) * (25.00 mL)

total moles of HCl added = 2.500 mmol

concentration of NaOH added = 0.1045 M

volume of NaOH added = 21.50 mL

moles of NaOH added = (concentration of NaOH added) * (volume of NaOH added)

moles of NaOH added = (0.1045 M) * (21.50 mL)

moles of NaOH added = 2.250 mmol

moles of HCl consumed by NaOH = moles of NaOH added

moles of HCl consumed by NaOH = 2.550 mmol

moles of HCl consumed by NH3 = (total moles of HCl added) - (moles of HCl consumed by NaOH)

moles of HCl consumed by NH3 = (2.500 mmol) - (2.250 mmol)

moles of HCl consumed by NH3 = .250 mmol

moles of NH3 present in cleaner sample = moles of HCl consumed by NH3

moles of NH3 present in cleaner sample = .250 mmol

concentration of NH3 sample = (moles of NH3 present in cleaner sample) / (volume of cleaner sample)

concentration of NH3 sample = (.250 mmol) / (25.00 mL)

concentration of NH3 sample = 0.01 M

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