If y^2-8xy = 10 then dy/dx = ?
回答 (3)
2020-08-07 12:56 am
✔ 最佳答案
2y * dy - 8 * x * dy - 8 * y * dx = 02y * dy - 8x * dy = 8y * dx
(2y - 8x) * dy = 8y * dx
dy/dx = 8y / (2y - 8x)
dy/dx = 4y / (y - 4x)
2020-08-07 2:25 am
y^2 = 8xy + 10...(1).;
Implicit differentiation of (1) gives 2y*y' = 8y + 8xy'. Then 2(y-4x)y' = 8y and;
y' = (dy/dx) = 4y/(y-4x), y =/= 4x for defined y'.
Implicit differentiation of (1) gives 2y*y' = 8y + 8xy'. Then 2(y-4x)y' = 8y and;
y' = (dy/dx) = 4y/(y-4x), y =/= 4x for defined y'.
收錄日期: 2021-04-18 18:37:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200806165244AAx7dWX