Fill in the missing value to make the log equation true. ?
回答 (6)
2020-08-09 10:51 am
log(6, 16)
= Log[16]/Log[6]
= 1.54741122...
= Log[16]/Log[6]
= 1.54741122...
2020-08-06 7:45 pm
16 = 2⁴
so, log₆16 => log₆(2⁴) = 4log₆2
:)>
so, log₆16 => log₆(2⁴) = 4log₆2
:)>
2020-08-06 7:34 pm
Notation: Put log(base 6) = L.
(C) states L16 = aL2 where a is unknown.;
But 16 = 2^4 so L16 = 4L2 = aL2. Obviously, a = 4.
(C) states L16 = aL2 where a is unknown.;
But 16 = 2^4 so L16 = 4L2 = aL2. Obviously, a = 4.
2020-08-06 4:20 pm
a * log[b](c) = log[b](c^a)
a * log[6](2) = log[6](16)
log[6](2^a) = log[6](16)
2^a = 16
2^a = 2^4
a = ?
a * log[6](2) = log[6](16)
log[6](2^a) = log[6](16)
2^a = 16
2^a = 2^4
a = ?
2020-08-06 7:06 pm
16 = 2^4, so, it follows that
log (to any base) of 16 is equal to
4*log (to same base) of 2
The missing number was 4
log (to any base) of 16 is equal to
4*log (to same base) of 2
The missing number was 4
收錄日期: 2021-04-24 07:58:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200806081245AA8hChJ