Express 0.5432 recurring decimals as fraction in their lowest term.?
回答 (2)
2020-08-04 1:36 pm
Let n = 0.54325432…… [i]
Then, 10000n = 5432.54325432…… [ii]
[ii] - [i]:
9999n = 5432
n = 5432/9999
Hence, 0.54325432…… = 5432/9999
Then, 10000n = 5432.54325432…… [ii]
[ii] - [i]:
9999n = 5432
n = 5432/9999
Hence, 0.54325432…… = 5432/9999
2020-08-04 11:56 am
0.(5432)^_ (repeating decimal)
= 5432/9999
= 5432/9999
收錄日期: 2021-04-24 07:55:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200804032526AAY7Z30