Can someone help me find x?
回答 (19)
2020-08-01 11:35 pm
Refer to the figure below.
According to intersecting chords theorem:
AS • SC = BS • SD
8 (x - 3) = 4 (x + 5)
8x - 24 = 4x + 20
4x = 44
x = 11
According to intersecting chords theorem:
AS • SC = BS • SD
8 (x - 3) = 4 (x + 5)
8x - 24 = 4x + 20
4x = 44
x = 11
2020-08-04 12:40 pm
One below the 8 and another below the 4. There is also a big x made of the lines going through the circle.
2020-08-02 6:08 am
x-3 / x + 5 = 1/2
2x - 6 = x + 5
x = 11
2x - 6 = x + 5
x = 11
2020-08-03 2:38 pm
There are two inside the circle.
2020-08-02 11:42 pm
1 is below the No. 8 & 1 is below the No. 4.
2020-08-02 7:40 am
Use the Intersecting Chords Theorem:
➤ Intersecting chords theorem:
— — states that the products of the lengths of the line segments on each chord are equal.
∴
8 ( x - 3 ) = 4 ( x + 5 )
8x - 24 = 4x + 20
8x - 4x = 20 + 24
4x = 44
x = 11
━━━
➤ Intersecting chords theorem:
— — states that the products of the lengths of the line segments on each chord are equal.
∴
8 ( x - 3 ) = 4 ( x + 5 )
8x - 24 = 4x + 20
8x - 4x = 20 + 24
4x = 44
x = 11
━━━
2020-08-02 1:02 am
Rectangular property of the intersecting chords says -
" When two chords intersect each other inside a circle, the products of their segments are equal."
Hence 4 * ( x + 5 ) = 8 * ( x - 3 )
=> 4 x + 20 = 8 x - 24
=> - 8 x + 4 x = - 24 - 20
=> - 4 x = - 44
=> x = 11 .............................. Answer
" When two chords intersect each other inside a circle, the products of their segments are equal."
Hence 4 * ( x + 5 ) = 8 * ( x - 3 )
=> 4 x + 20 = 8 x - 24
=> - 8 x + 4 x = - 24 - 20
=> - 4 x = - 44
=> x = 11 .............................. Answer
2020-08-02 12:44 am
If two chords intersect inside a circle,
then the product of the lengths of the segments of one chord
equals the product of the lengths of the segments of the other chord. N ⋅ M = L ⋅ M.
8(x - 3) = 4(x + 5)
x = 11
then the product of the lengths of the segments of one chord
equals the product of the lengths of the segments of the other chord. N ⋅ M = L ⋅ M.
8(x - 3) = 4(x + 5)
x = 11
2020-08-02 12:04 am
It's hiding under the bed.
2020-08-02 11:16 pm
There are two x's, both next to an arithmetic operator and an integer.
2020-08-04 1:14 am
Error: the asker must point out if the figure is
a circle.
Assume the given figure is a circle. Let
the chord containing "8 & x+3" be AB; the chord
containing " 4 & x+5" be CD. They intersect at O. Join AD & CB, then there are 2 similar triangles Tri. AOD & BOC. Thus,
AO/CO=DO/BO
=>
8/(x+5)=4/(x-3)
=>
2x-6=x+5
=>
x=11
a circle.
Assume the given figure is a circle. Let
the chord containing "8 & x+3" be AB; the chord
containing " 4 & x+5" be CD. They intersect at O. Join AD & CB, then there are 2 similar triangles Tri. AOD & BOC. Thus,
AO/CO=DO/BO
=>
8/(x+5)=4/(x-3)
=>
2x-6=x+5
=>
x=11
2020-08-02 3:41 am
8(x - 3) = 4(x + 5)
8x - 4x = 20 + 24
4x = 44
x = 11
8x - 4x = 20 + 24
4x = 44
x = 11
2020-08-02 6:48 pm
4(x + 5) = 8(x - 3)
Take it from here.
Take it from here.
2020-08-02 8:06 am
If I do that then all you'll learn is that I know how to do it.
2020-08-01 11:17 pm
8 +4 + x + 5 +x -3= 360 degrees
10 + 2x = 360
2x= 360 -10
2x =35
x= 17.5 degrees
10 + 2x = 360
2x= 360 -10
2x =35
x= 17.5 degrees
2020-08-05 12:11 am
the solution will be 4 * (x+5)= 8 * (x-3) it gives x =11
2020-08-03 10:46 am
Note that both chords* are inside a circle, this permits we to use the
Interesecting Chords Theorem:
"the products of the lengths of the line segments on each chord are equals"
So we have: 4.(x + 5) = 8 (x-3)
Expanding:
4x + 20 = 8x -24
Isolate x:
-4x = -44
x = 11
* Chord: segment that joins two points of a circle.
Interesecting Chords Theorem:
"the products of the lengths of the line segments on each chord are equals"
So we have: 4.(x + 5) = 8 (x-3)
Expanding:
4x + 20 = 8x -24
Isolate x:
-4x = -44
x = 11
* Chord: segment that joins two points of a circle.
2020-08-02 2:18 am
4x+20=8x-24
-4x=-24-20
4x=44>>x=11
-4x=-24-20
4x=44>>x=11
收錄日期: 2021-04-18 18:35:16
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