Chemistry question. A balloon is brought to the top of Mt. Logan where it occupies a volume of 775 mL at a temperature of –28ºC... ?
2020-07-30 1:15 am
A balloon is brought to the top of Mt. Logan where it occupies a volume of 775 mL at a temperature of –28ºC and a pressure of 92.5 kPa. What is the pressure at the bottom of the mountain if the same balloon has a volume of 825 mL at a temperature of 15ºC?
回答 (1)
2020-07-30 1:22 am
Top of Mt. Logan: P₁ = 92.5 kPa, V₁ = 775 mL, T₁ = (273 - 28) K = 245 K
Bottom of Mt. Logan: P₂ = ? kPa, V₂ = 825 mL, T₂ = (273 + 15) K = 288 K
Combined gas law: P₁V₁/T₁ = P₂V₂/T₂
Then, P₂ = P₁ × (V₁/V₂) × (T₂/T₁)
Pressure at the bottom of Mt. Logan, P₂
= 92.5 × (775/825) × (288/245) kPa
= 102 kPa
Bottom of Mt. Logan: P₂ = ? kPa, V₂ = 825 mL, T₂ = (273 + 15) K = 288 K
Combined gas law: P₁V₁/T₁ = P₂V₂/T₂
Then, P₂ = P₁ × (V₁/V₂) × (T₂/T₁)
Pressure at the bottom of Mt. Logan, P₂
= 92.5 × (775/825) × (288/245) kPa
= 102 kPa
收錄日期: 2021-04-24 07:56:00
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