Physics work problem?

F₁ = 10.0 N which makes an angle of 210° with the +x-axis.
Hence, F₁ = [10.0 cos(210°) i + 10.0 sin(210°) j] N

F₂ = 8.00 N which makes an angle of 75° with the +x-axis.
Hence, F₂ = [8.00 cos(75°) i + 8.00 sin(75°) j] N

The resultant force
= [10.0 cos(210°) i + 10.0 sin(210°) j] N + [8.00 cos(75°) i + 8.00 sin(75°) j] N
= [10.0 cos(210°) + 8.00 cos(75°)] i N+ [10.0 sin(210°) + 8.00 sin(75°) ] j N
= (-6.6 i + 2.7 j) N

The answer: None of the five options is the answer

However, if there is a typo in option D and it is (-6.6 i + 2.7 j) N instead. The answer is then:
D. (-6.6 i + 2.7 j) N

Resolving in the i and j directions we have:

(→) 10cos210 + 8cos75 => -6.6

(↑) 10sin210 + 8sin75 => 2.7

i.e. (-6.6i + 2.7j) Newtons

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This always works as long as your angles are on a 360° circle as they are here.
Sum horizontal components:
10cos210 + 8cos75 = -6.6 
Sum vertical components:
10sin210 + 8sin75 = 2.7
The answer is D but it has a typo.  It should be:
D. (-6.6i + 2.7j)N