An equilibrium mixture of the following reaction was found to have [I2]=0.0375M at 1200 ∘C:
I2(g)⇌2I(g)
Keq=1.2×10−2 at 1200 ∘C
What is the concentration of I ?
2020-07-28 3:31 pm
回答 (1)
2020-07-28 7:24 pm
I₂(g) ⇌ 2I(g) Keq = 1.2 × 10⁻²
Eqm: 0.0375 M ? M:
Keq = [I]² / [I₂]
1.2 × 10⁻² = [I]² / (0.0375)
[I] = √(0.0375 × 1.2 × 10⁻²) M
Concentration of I, [I] = 0.0212 M
Eqm: 0.0375 M ? M:
Keq = [I]² / [I₂]
1.2 × 10⁻² = [I]² / (0.0375)
[I] = √(0.0375 × 1.2 × 10⁻²) M
Concentration of I, [I] = 0.0212 M
收錄日期: 2021-04-24 07:58:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200728073100AA5B6Us