A balloon contains 125 L of air at 35oC. ?
2020-07-28 2:36 pm
A balloon contains 125 L of air at 35oC. What will the new volume of the balloon be if the temperature drops to -35oC while the pressure is kept constant?
回答 (2)
2020-07-28 2:45 pm
Original: V₁ = 125 L, T₁ = (273 + 35) K = 308 K
New: V₂ = ? kPa, T₂ = (273 - 35) K = 238 mL
For a fixed amount of gas under constant pressure: V₁/T₁ = V₂/T₂
Then, V₂ = V₁ × (T₂/T₁)
New volume, V₂ = 125 × (238/308) L = 96.6 L
New: V₂ = ? kPa, T₂ = (273 - 35) K = 238 mL
For a fixed amount of gas under constant pressure: V₁/T₁ = V₂/T₂
Then, V₂ = V₁ × (T₂/T₁)
New volume, V₂ = 125 × (238/308) L = 96.6 L
2020-07-28 2:44 pm
P * V = n * R * T
V / T = n * R / P
n stays the same
R is a constant
P stays the same
n * R / P can be rewritten as some constant k
V/T = k
V[1] / T[1] = k
V[2] / T[2] = k
k = k
therefore
V[1] / T[1] = V[2] / T[2]
T is measured in Kelvins
125 / (273.15 + 35) = V[2] / (273.15 - 35)
125 * (273.15 - 35) / (273.15 + 35) = V[2]
V = 125 * 238.15 / 308.15
V = 125 * 23815/30815
V = 125 * (47630 / 2) / (61630 / 2)
V = 125 * (4763/6163)
V = 96.6047379522959597598572123965...
To 3 sf
96.6 Liters
V / T = n * R / P
n stays the same
R is a constant
P stays the same
n * R / P can be rewritten as some constant k
V/T = k
V[1] / T[1] = k
V[2] / T[2] = k
k = k
therefore
V[1] / T[1] = V[2] / T[2]
T is measured in Kelvins
125 / (273.15 + 35) = V[2] / (273.15 - 35)
125 * (273.15 - 35) / (273.15 + 35) = V[2]
V = 125 * 238.15 / 308.15
V = 125 * 23815/30815
V = 125 * (47630 / 2) / (61630 / 2)
V = 125 * (4763/6163)
V = 96.6047379522959597598572123965...
To 3 sf
96.6 Liters
收錄日期: 2021-04-24 07:57:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200728063617AABkyv8