At constant temperature, a 600 mL volume of gas has a pressure of 101 kPa. If the volume is decreased to 300 mL, the pressure will be:?
回答 (1)
2020-07-28 2:39 pm
✔ 最佳答案
Original: P₁ = 101 kPa, V₁ = 600 mLNew: P₂ = ? kPa, V₂ = 300 mL
Boyle's law: P₁V₁ = P₂V₂
Then, P₂ = P₁ × (V₁/V₂)
New pressure, P₂ = 101 × (600/300) kPa = 202 kPa
收錄日期: 2021-04-18 18:34:08
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