According to Le Chantlier's principle, if the reaction at equilibrium which of the following disturbance will shift the reaction to the righ?

According to the Le Chatelier's principle, if the concentration a reactant (Fe³⁺(aq) or SCN⁻(aq)) increases or the concentration of the product (Fe(SCN)²⁺(aq)) decreases, the reaction will shift to the right in order to counteract the disturbance.

The answers:
Increase the concentration of Fe³⁺(aq)
Decrease the concentration of Fe(SCN)²⁺(aq)
Increase the concentration of SCN⁻(aq)

LeChatlier's principle says that the reaction will shift right if you add reactants or remove products.

The principle states that if an equilibrium is disturbed, then the system will move in such a way as to minimise that disturbance. 

So for the given reaction at equil'm , if you add more Fe^3+ you are disturbing the system. So it will move to minimise that disturbance. So it will use up up as much of the Fe^3+ as it can and reach a new equil'm position.  So more Fe(SCN)^2+ is created. The system moves to the right. 

However, the concentrations at the new equilibrium will be different, because you have NOT  added any SCN^- . 

So the three disturbances are 1st,  4th, & 5th. ; These will shift the system to the right.