probability question?

The table below shows the sums of rolling two dice A and B.
The sum is shown in red if it is even, and in blue if it is odd.
Total number of outcomes without restriction = 6 × 6 = 36

i)
There is only 1 outcome for Snake Eyes.
P(Snake Eyes)
= 1/36

ii)
There are 1 sum of "2", 2 sums of "3" and 2 sums of "4" when the sum is not greater than 4.
There are 36 - (1 + 2 + 3) = 30 outcomes when the sum greater than 4.
P(a sum greater than 4)
= 30/36
= 5/6

iii)
The even sums are shown in blue. There are 18 even sums.
P(an even sum)
= 18/36
= 1/2

iv)
Die A is '3' for the column (4, 5, 6, 7, 8, 9). Die is "3" for the row (4, 5, 6, 7, 8, 9). A "6" is overlapped.
When there is at least one die is a "3", there are 6 × 2 - 1 = 11 outcomes.
P(at least one die is a 3)
= 11/36

v)
The odd sums are shown in red. There are 18 odd sums. There are 5 outcomes if the sum is '8".
There are totally 18 + 5 = 23 outcomes.
P(an odd sum of a sum of 8)
= 23/36

Hint: Google images, 2 dice roll. You will see 36 combos.

Out of those, answer your questions!

Un-anon yourself and we will detail further if need be. 

The numerator is the number of times you see the desired outcome.
The denominator is the total possible rolls (6 * 6 = 36)
Reduce the fraction.

The following diagram should help.