Find a value of alpha in the interval [0 degrees, 90 degrees] that satisfies the given statement: cot alpha = 1.4895954. ?
回答 (2)
2020-07-24 10:18 pm
cot(α) = 1.4895954
tan(α) = 1/cot(α)
tan(α) = 1/1.4895954
α = tan⁻¹(1/1.4895954)
By using a calculator, α = 33.874380°
tan(α) = 1/cot(α)
tan(α) = 1/1.4895954
α = tan⁻¹(1/1.4895954)
By using a calculator, α = 33.874380°
2020-07-24 10:45 pm
I'm replacing your alpha with x. Find x in (0,90) such that cotx = 1.4895954.;
For such x we have tanx = 1/cotx = 1/1.4895954 = 0.6713232331. Then x =;
arctan(0,6713232331) = 33.87437957 degrees. I hope your calculator has the
arctan function.
For such x we have tanx = 1/cotx = 1/1.4895954 = 0.6713232331. Then x =;
arctan(0,6713232331) = 33.87437957 degrees. I hope your calculator has the
arctan function.
收錄日期: 2021-04-18 18:34:34
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