If the gas is heated at constant pressure until its volume is 632 mL, the temperature of the gas sample will be
°C.
A sample of neon gas at a pressure of 0.702 atm and a temperature of 241 °C, occupies a volume of 518 mL. ?
2020-07-23 9:19 pm
回答 (1)
2020-07-23 10:15 pm
Original: T₁ = (273 + 241) K = 514 K, V₁ = 518 mL
New: T₂ = ? K, V₂ = 632 mL
For a fixed amount of gas under constant pressure: V₁/T₁ = V₂/T₂
Then, T₂ = T₁ × (V₂/V₁)
New temperature, T₂ = 514 × (632/518) K = 627 K = 354 °C
New: T₂ = ? K, V₂ = 632 mL
For a fixed amount of gas under constant pressure: V₁/T₁ = V₂/T₂
Then, T₂ = T₁ × (V₂/V₁)
New temperature, T₂ = 514 × (632/518) K = 627 K = 354 °C
收錄日期: 2021-04-18 18:35:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200723131955AAzmHQN