An object 4.56 centimeters tall is placed 78.3 centimeters in front of a diverging lens. The lens has a focal length of 45.9 centimeters. ?

(1/u) + (1/v) = 1/f
(1/78.3) + (1/v) = -1/45.9
1/v = -(1/45.9) - (1/78.3)
v = 1 / [-(1/45.9) - (1/78.3)]
Image distance, v = -28.9 cm

Height of the image = 4.56 × |v/u| = 4.56 × |-28.9/78.3| = 1.68 cm

Since v is negative, the image is virtual.

Since v is negative, the image is upright.

The answers:
How tall is the image? 1.68 cm
How far from the lens is the image? 28.9 cm
Is the image virtual or real? virtual
Is it upright or inverted? upright

BY 1/do + 1/di = 1/f
=>1/78.3 + 1/di = 1/(-45.9)
=>1/di = -1/78.3 - 1/45.9
=>di = -28.94 cm --------------Answer (ii)
By m = -di/do = hi/ho
=>hi = -di x ho/do = -(-28.94) x 4.56/78.3 = 1.69 cm -----------Answer (i)
As di is -ve =>virtual ------------Answer (iii)
As m -s +ve =>upright-------------Answer (iv)

How tall is the image? = 4.56 cm
How far from the lens is the image?  = 78.3 cm
Is the image virtual or real? = it's real
Is it upright or inverted? = I think inverted