Answer the question in the photo below!?

Molar mass of H₂O = (1.0×2 + 16.0×2) g/mol = 18.0 g/mol
Molar mass of C₂H₅OH = (12.0×2 + 1.0×6 + 16.0) g/mol = 46.0 g/mol

C₂H₄ + H₂O → C₂H₅OH
Mole ratio H₂O : C₂H₅OH = 1 : 1

Moles of H₂O reacted = (72.1 g) / (18.0 g/mol) = 4.01 mol
Moles of C₂H₅OH produced = 4.01 mol
Mass of C₂H₅OH produced = (4.01 mol) × (46.0 g/mol) = 184 g

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OR:

(72.1 g H₂O) × (1 mol H₂O / 18.0 g H₂O) × (1 mol C₂H₅OH / 1 mol H₂O) × (46.0 g C₂H₅OH / 1 mol C₂H₅OH)
= 184 g C₂H₅OH

There is a 1:1 ratio of water to ethanol from the reaction, So:

72.1g / 18g/mol = 4.01 moles

4.01 moles X 36g/mol = 144 grams