what mass of LiOH must be added to 750.0 mL of 0.0550 M HCl to create a mixture having a pH of 2.500?

Equation for the reaction:
LiOH + HCl → LiCl + H₂O
Mole ratio LiOH : HCl = 1 : 1

[H⁺] of the solution after addition of LiOH = 10⁻²˙⁵⁰⁰ = 0.003162 mol/L
Moles of excess HCl = (0.003162 mol/L) × (750.0/1000 L) = 0.00237 mol

Initial moles of HCl = (0.0550 mol/L) × (750.0/1000 L) = 0.04125 mol
Moles of HCl reacted with LiOH = (0.04125 - 0.00237) = 0.03888 mol
Moles of LiOH added = 0.03888 mol

Molar mass of LiOH = (6.94 + 16.00 + 1.01) g/mol = 23.95 g/mol
Mass of LiOH added = (0.03888 mol) × (23.95 g/mol) = 0.9311 g