A sample of O2 wa @ 397K was heated to 433K. If the volume of the oxygen gas sample @ 433K is 636.1mL, what is the volume @ 379k? ?

2020-07-21 3:14 pm
Chemistry 

回答 (1)

2020-07-21 3:23 pm
Case 1: 397 K

For the sample of O₂:
Original: T₁ = 397 K, V₁ = ? mL
New: T₂ = 433 K, V₂ = 636.1 mL

For a fixed amount of gas at constant pressure: V₁/T₁ = V₂/T₂
Then, V₁ = V₂ × (T₁/T₂)

Volume at 397 K, V₁ = 636.1 × (397/433) mL = 583.2 mL

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Case 2: 379 K

For the sample of O₂:
Original: T₁ = 379 K, V₁ = ? mL
New: T₂ = 433 K, V₂ = 636.1 mL

For a fixed amount of gas at constant pressure: V₁/T₁ = V₂/T₂
Then, V₁ = V₂ × (T₁/T₂)

Volume at 379 K, V₁ = 636.1 × (379/433) mL = 556.8 mL


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