A certain reaction has an activation energy of 60.0 kJ/mol and a frequency factor ?
2020-07-21 10:42 am
A certain reaction has an activation energy of 60.0 kJ/mol and a frequency factor of A1 = 7.80×1012 M−1s−1 . What is the rate constant, k, of this reaction at 23.0 ∘C ?
回答 (4)
2020-07-21 12:53 pm
Eₐ = 60 kJ/mol = 60000 J mol⁻¹
R = 8.314 J mol⁻¹ K⁻¹
T = (273.2 + 23.0) K = 296.2 K
A = 7.80 × 10¹² M⁻¹ s⁻¹
R = 8.314 J mol⁻¹ K⁻¹
T = (273.2 + 23.0) K = 296.2 K
A = 7.80 × 10¹² M⁻¹ s⁻¹
2020-07-21 11:25 am
use the arrhenius equation
.. k = Ao exp(-Ea / RT)
.. k = Ao exp(-Ea / RT)
2020-07-21 11:40 am
k = A e^-Ea/RT
k= 7.80×10^12 M−1s−1 . e^ -60kj/mol /0.0083144kj/mol.K * 296K
k= 7.80×10^12 M−1s−1 . e^ -60kj/mol /0.0083144kj/mol.K * 296K
2020-07-21 11:14 am
According to Arrhenius Equation:
K = Ae^(-Ea/RT);
K = (7.80*10^12 M−1s−1)e^((-60000 J/mol)/(8.314 J/K·mol)(296.15 K))
K = (7.8*10^12)e^((-60000 )/((8.314)*(296.15))
K = 6.80 x 10^(12)
K = Ae^(-Ea/RT);
K = (7.80*10^12 M−1s−1)e^((-60000 J/mol)/(8.314 J/K·mol)(296.15 K))
K = (7.8*10^12)e^((-60000 )/((8.314)*(296.15))
K = 6.80 x 10^(12)
收錄日期: 2021-04-18 18:36:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200721024229AAgggm2