For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 2Al(s)+3Cl2(g)→2AlCl3(s)?

Molar mass of Al = 27.0 g/mol
Molar mass of Cl₂ = 35.5×2 g/mol = 71.0 g/mol

2Al(s) + 3Cl₂(g) → 2AlCl₃(s)
Mole ratio Al : Cl₂ = 2 : 3

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1.0 g Al; 1.0 g Cl₂

Initial moles of Al = (1.0 g) / (27.0 g/mol) = 0.037 mol
Initial moles of Cl₂ = (1.0 g) / (71.0 g/mol) = 0.014 mol

If 0.037 mol Al completely reacts,
moles of Cl₂ needed = (0.037 mol) × (3/2) = 0.056 mol > 0.014 mol
Hence, Cl₂ is the limiting reactant.

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2.2 g Al; 1.8 g Cl₂

Initial moles of Al = (2.2 g) / (27.0 g/mol) = 0.081 mol
Initial moles of Cl₂ = (1.8 g) / (71.0 g/mol) = 0.025mol

If 0.081 mol Al completely reacts,
moles of Cl₂ needed = (0.081 mol) × (3/2) = 0.12 mol > 0.025 mol
Hence, Cl₂ is the limiting reactant.

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0.353 g Al; 0.482 g Cl₂

Initial moles of Al = (0.353 g) / (27.0 g/mol) = 0.0131 mol
Initial moles of Cl₂ = (0.482 g) / (71.0 g/mol) = 0.00679 mol

If 0.0131 mol Al completely reacts,
moles of Cl₂ needed = (0.0131 mol) × (3/2) = 0.0197 mol > 0.00679 mol
Hence, Cl₂ is the limiting reactant.

note1: never answer with more digits than was given!
note2: I use (converters) in parens, canceling units. Not hard at all.

The technique is simple, always multiply by (1) canceling units.
1. Write down your "given" value (start right side up!)
2. Multiply by (1)
3. Cancel units until you get what you're looking for!
Many of us call this the "Unit Cancellation Method" or Dimensional Analysis.
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Example 1:6 in to feet: 6in (1ft/12in) = .5 ft

Example 2:You can even 'chain' multiple converters together, hence why I love to use each converter in (parens).122 in to miles:122in (1ft/12in)(1mi/5280ft) = 0.001925 mi

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This technique is VERY powerful yet easy to learn and use! If you take the time to learn it, it can be used almost everywhere in real life!

Here's a 2-minute video that teaches this method, 2 minutes to help you for a lifetime!!!
www.youtube.com/watch?v=8jB-LaTGgq8