The rate of a chemical reaction triples when the temperature increases
from 45 °C to 75 °C . Assume you are asked to calculate the activation energy for the
reaction. Write the equation that you would use to solve a problem like this. Then fill
in the numerical values for all of the variables, except Ea; also fill in a value for R. Do
not attempt to solve for Ea.
Activation energy?
2020-07-14 4:24 pm
回答 (1)
2020-07-14 4:41 pm
✔ 最佳答案
When T₁ = (273 + 45) K = 318 K: k₁ = kWhen T₂ = (273 + 75) K = 348 K: k₂ = 3k
ln(k₁/k₂) = (Eₐ/R) [(1/T₂) - (1/T₁)]
ln(1/3) = (Eₐ/8.314) [(1/348) - (1/318)]
Solve for Eₐ with units J/mol.
收錄日期: 2021-04-18 18:33:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200714082427AAHJ5Y9