若a<-3，則不等式ax-a加3x>3的解為?
回答 (1)
2020-07-10 7:42 pm
a < -3
∴ a + 3 < 0
ax - a + 3x > 3
<==> ax + 3x > a + 3
<==> (a+3)x > a+3
<==> x < 1
∴ a + 3 < 0
ax - a + 3x > 3
<==> ax + 3x > a + 3
<==> (a+3)x > a+3
<==> x < 1
收錄日期: 2021-05-04 02:29:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200710104942AATTYyc