A Ni-Cd rechargeable cell has a cell potential of +1.30 V. If the cathode has a potential of +0.49 V, what is the anode’s potential? ?
回答 (1)
2020-07-06 4:36 pm
✔ 最佳答案
E(cell) = E(reduction) - E(oxidation)Hence, E(cell) = E(cathode) - E(anode)
(+1.30 V) = (+0.49 V) - E(anode)
Anode's potential, E(anode) = +(0.49 - 1.30) V = -0.81 V
收錄日期: 2021-04-18 18:35:29
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