✔ 最佳答案
Initial moles of FeCl₃ = 4 mol
Initial moles of O₂ = 4 mol
Balanced equation for the reaction:
4FeCl₃ + 3O₂ → 2Fe₂O₃ + 6Cl₂
Mole ratio FeCl₃ : O₂ = 4 : 3
Obviously, when 4 mol of FeCl₃ completely reacts, O₂ needed = 3 mol < 4 mol
Hence, O₂ is in excess and FeCl₃ is the limiting reactant (limiting reagent).
According to the above equation, mole ratio FeCl₃ : Cl₂ = 4 : 6
Moles of Cl₂ gas produced = (4 mol) × (6/4) = 6 mol