if g(x)=1-3x and f(x)=9x^2-6x+5, determine value of f(5)?
回答 (4)
2020-07-06 12:59 am
f(x) = 9x² - 6x + 5
f(5) = 9(5)² - 6(5) + 5
f(5) = 225 - 30 + 5
f(5) = 200
(The given g(x) is redundant.)
f(5) = 9(5)² - 6(5) + 5
f(5) = 225 - 30 + 5
f(5) = 200
(The given g(x) is redundant.)
2020-07-06 7:57 pm
f(x) = 9x^2- 6x+5
f(5) = 9(5)^2 - 6(5) + 5 = 200 Answer//
f(5) = 9(5)^2 - 6(5) + 5 = 200 Answer//
2020-07-06 4:50 am
g(x) = 1 - 3x
f(x) = 9x² - 6x + 5
// This question has nothing
// to do with g(x)
f(5) = 9(5)² - 6(5) + 5
......= 9(25) - 30 + 5
......= 200......................ANS
f(x) = 9x² - 6x + 5
// This question has nothing
// to do with g(x)
f(5) = 9(5)² - 6(5) + 5
......= 9(25) - 30 + 5
......= 200......................ANS
2020-07-06 2:26 am
f(x) = 9x^2 - 6x + 5
f(5) = 225 - 30 + 5 = 200
f(5) = 225 - 30 + 5 = 200
收錄日期: 2021-04-18 18:32:54
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