Calculate the amount of force exerted by the atmosphere on the roof of your house (area = 95 m2) if the pressure is 101,000 Pa.?
回答 (3)
2020-06-15 6:01 pm
Force, F
= P A
= (101,000 N/m²) × (95 m²)
= 9,600,000 N (to 2 sig. fig.)
= P A
= (101,000 N/m²) × (95 m²)
= 9,600,000 N (to 2 sig. fig.)
2020-06-16 12:00 am
outer force OF = 95*1.01000*10^5 = 9.6*10^6 N
inner force IF = -OF = -9.6*10^6 N
net force NF = OF+IF = 9.6*10^6-9.6*10^6 = 0
inner force IF = -OF = -9.6*10^6 N
net force NF = OF+IF = 9.6*10^6-9.6*10^6 = 0
2020-06-15 6:39 pm
zero, the forces on the top of the roof pushing down balance those under the roof pushing up. There is a small difference, but that depends on the thickness of the roof and it pushes up by a tiny amount.
收錄日期: 2021-04-18 18:31:46
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