A parallel circuit has three light bulbs with 3 currents: 2A, 3A and 4A. How much current is leaving the battery? ?
回答 (1)
Current leaving the battery
= (2 + 3 + 4) A
= 9A
收錄日期: 2021-04-18 18:32:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200610145005AAm0VYc
檢視 Wayback Machine 備份