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In a chemical analysis, only one quantitative could be detected in the pH curve for the reaction of sodium sulfide with hydrochloric acid. In a subsequent titration, 10.0 mL of Na2SO3(aq) was titrated with 0.225 mol/L HCl(aq). The average volume of titrant to reach the endpoint was 14.2 mL. What is the concentration of the Na2SO3(aq) solution?
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2020-06-10 2:57 pm
回答 (1)
2020-06-10 3:08 pm
Equation for the reaction:
Na₂SO₃ + 2HCl → 2NaCl + H₂O + SO₂
Mole ratio Na₂SO₃ + HCl = 1 : 2
Moles of HCl reacted = (0.225 mol/L) × (14.2/1000 L) = 0.003195 mol
Moles of Na₂SO₃ reacted = (0.003195 mol) × (1/2) = 0.00160 mol
Concentration of Na₂SO₃ = (0.00160 mol) / (10.0/1000) = 0.160 M
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OR:
(0.225 mol HCl / 1000 mL HCl) × (14.2 mL HCl) × (1 mol Na₂SO₃ / 2 mol HCl) / (10.0 mL Na₂SO₃)
= 0.160 M
Na₂SO₃ + 2HCl → 2NaCl + H₂O + SO₂
Mole ratio Na₂SO₃ + HCl = 1 : 2
Moles of HCl reacted = (0.225 mol/L) × (14.2/1000 L) = 0.003195 mol
Moles of Na₂SO₃ reacted = (0.003195 mol) × (1/2) = 0.00160 mol
Concentration of Na₂SO₃ = (0.00160 mol) / (10.0/1000) = 0.160 M
====
OR:
(0.225 mol HCl / 1000 mL HCl) × (14.2 mL HCl) × (1 mol Na₂SO₃ / 2 mol HCl) / (10.0 mL Na₂SO₃)
= 0.160 M
收錄日期: 2021-04-18 18:33:33
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https://hk.answers.yahoo.com/question/index?qid=20200610065744AAa17NS