pls help asap?
2020-06-07 2:39 pm
Find the first 5 terms of the sequence with a(sub 1) = -2 and a(sub n) = 3a(sub n - 1) + 2 for n ≥ 2.
回答 (2)
2020-06-07 2:44 pm
The first five terms of the sequence:
a₁ = -2
a₂ = 3a₁ + 2 = 3(-2) + 2 = -4
a₃ = 3a₂ + 2 = 3(-4) + 2 = -10
a₄ = 3a₃ + 2 = 3(-10) + 2 = -28
a₅ = 3a₄ + 2 = 3(-28) + 2 = -82
a₁ = -2
a₂ = 3a₁ + 2 = 3(-2) + 2 = -4
a₃ = 3a₂ + 2 = 3(-4) + 2 = -10
a₄ = 3a₃ + 2 = 3(-10) + 2 = -28
a₅ = 3a₄ + 2 = 3(-28) + 2 = -82
2020-06-07 2:43 pm
a(n) = 3a(n-1) + 2
a(1) = -2
a(2) = 3(-2) + 2 = -6 + 2 = -4
a(3) = 3(-4) + 2 = -12 + 2 = -10
a(4) = 3(-10) + 2 = -30 + 2 = -28
a(5) = 3(-28) + 2 = -84 + 2 = -82
a(1) = -2
a(2) = 3(-2) + 2 = -6 + 2 = -4
a(3) = 3(-4) + 2 = -12 + 2 = -10
a(4) = 3(-10) + 2 = -30 + 2 = -28
a(5) = 3(-28) + 2 = -84 + 2 = -82
收錄日期: 2021-05-01 01:01:14
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