CHEM HELP ASAP PLEASE EXPLAIN?
回答 (1)
2020-06-01 9:03 pm
002
pH = -log[H₃O⁺] = 8.56
[H₃O⁺] = 10⁻⁸˙⁵⁶ M = 2.75 × 10⁻⁹ M
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003
pOH = pKw - pH = 14.00 - 8.56 = 5.44
p0H = -log[OH⁻] = 5.44
[H₃O⁺] = 10⁻⁵˙⁴⁴ M = 3.63 × 10⁻⁶ M
pH = -log[H₃O⁺] = 8.56
[H₃O⁺] = 10⁻⁸˙⁵⁶ M = 2.75 × 10⁻⁹ M
====
003
pOH = pKw - pH = 14.00 - 8.56 = 5.44
p0H = -log[OH⁻] = 5.44
[H₃O⁺] = 10⁻⁵˙⁴⁴ M = 3.63 × 10⁻⁶ M
收錄日期: 2021-04-18 18:31:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200601125703AAZZju4