Enthalpy Change For The Forward Reaction?
2020-05-31 3:00 pm
I am having trouble finding the enthalpy change for the forward reaction. I keep getting 100 kJ, but that isn't the right answer.
回答 (1)
2020-05-31 3:16 pm
Enthalpy change of the forward reaction
= (P.E. of products) - (P.E. of reactants)
= (200 - 100) kJ
= +100 kJ
= (P.E. of products) - (P.E. of reactants)
= (200 - 100) kJ
= +100 kJ
收錄日期: 2021-05-01 09:36:14
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