The electric output of a power plant is 800 MW . Cooling water flows through the power plant at the rate 0.900 ×108L/hr. The cooling water enters the plant at 13.0ºC and exits at 26.0ºC .
What is the power plant's thermal efficiency?
thanks
What is the power plant's thermal efficiency?
2020-05-31 1:32 pm
回答 (1)
2020-05-31 3:29 pm
Density of water = 1.00 g/cm³
Flow rate of water = (0.900 × 10⁸ L/hr) × (1000 cm³/L) = 9.00 × 10¹⁰ g/hr
Power loss per second
= m c ΔT / t
= (9.00 × 10¹⁰ g) × (4.184 J/g°C) × [(26.0 - 13.0)°C] / (3600 s)
= 136 × 10⁶ W
= 136 MW
Thermal efficiency = [800 / (800 + 136)] × 100% = 85.5%
Flow rate of water = (0.900 × 10⁸ L/hr) × (1000 cm³/L) = 9.00 × 10¹⁰ g/hr
Power loss per second
= m c ΔT / t
= (9.00 × 10¹⁰ g) × (4.184 J/g°C) × [(26.0 - 13.0)°C] / (3600 s)
= 136 × 10⁶ W
= 136 MW
Thermal efficiency = [800 / (800 + 136)] × 100% = 85.5%
收錄日期: 2021-04-18 18:30:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200531053222AA8PY99