Molarity question?
2020-05-31 1:24 pm
A 2.00 g piece of aluminum is cut from an aluminum pie pan. It is submersed in an aqueous solution of 3.30 g of copper(II)chloride in 325 mL of solution. This reaction is described by the balanced equation above. What is the molarity of the original solution of copper(II) chloride?
回答 (3)
2020-05-31 2:32 pm
The question can be simplified as to calculate the molarity of copper(II) chloride solution which is made by dissolving 3.30 g of copper(II) chloride to make 325 mL aqueous solution.
Hence, the given mass of aluminum and the equation (actually it is not given) are redundant.
Molar mass of CuCl₂ = (63.5 + 35.5×2) g/mol = 134.5 g/mol
Molarity of the original CuCl₂ solution = (3.30/134.5 mol) /(325/1000 L) = 0.0755 M
Hence, the given mass of aluminum and the equation (actually it is not given) are redundant.
Molar mass of CuCl₂ = (63.5 + 35.5×2) g/mol = 134.5 g/mol
Molarity of the original CuCl₂ solution = (3.30/134.5 mol) /(325/1000 L) = 0.0755 M
2020-05-31 2:42 pm
(3.30 g CuCl2) / (134.452 g CuCl2/mol) / (0.325 L) = 0.0755 mol/L CuCl2
2020-05-31 1:28 pm
sounds complicated. how would YOU start such a problem???
收錄日期: 2021-04-24 07:54:39
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https://hk.answers.yahoo.com/question/index?qid=20200531052445AAkJChe