Please, explain?
回答 (4)
2020-05-31 4:09 am
The Chain Rule: dz/dx = (dz/dy)•(dy/dx)
So, where f = f(y), df/dx = (df/dy)•(dy/dx)
d(f(y))/dx = (d(f(y))/dy)•(dy/dx)
Answer D
So, where f = f(y), df/dx = (df/dy)•(dy/dx)
d(f(y))/dx = (d(f(y))/dy)•(dy/dx)
Answer D
2020-05-31 10:00 am
(df(y))/(dx) = d/(dy)(f(y)×(df(y))/(dx))
2020-05-31 4:27 am
d...............d.............dy
--- (f(y)) = --- (f(y)) • ---............ANS (Option D)
dx.............dx...........dx
--- (f(y)) = --- (f(y)) • ---............ANS (Option D)
dx.............dx...........dx
2020-05-31 4:12 am
Yes D) is correct ; .....df / dx ≡ ( df / dw ) ( dw / dt ) (dt/dx) by the theorem on derivatives of Composite Functions...in algebra you remember that [ A B C } / [ B C H ] ≡ A / H...same holds for derivatives using ' symbols '
收錄日期: 2021-04-24 07:54:02
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