If 24.0 mL of 0.10 M Ba(NO3)2 are added to 64.0 mL of 0.17 M Na2CO3, will BaCO3 precipitate? Then Calculate Q. show all work please?

Refer to: https://www.chm.uri.edu/weuler/chm112/refmater/KspTable.html
Ksp for BaCO₃ = 5.1 × 10⁻⁹
Ksp from different sources may be slightly different.

Volume of the final solution = (24.0 + 64.0) mL = 88.0 mL

Dilution just after mixing:
[Ba²⁺] = [Ba(NO₃)₂] = (0.10 M) × (24.0/88.0) = 0.0273 M
[CO₃²⁻] = [Na₂CO₃] = (0.17 M) × (64.0/88.0) = 0.124 M

BaCO₃(s) ⇌ Ba²⁺(aq) + CO₃²⁻(aq)   Ksp = 5.1 × 10⁻⁹
Reaction quotient, Q = [Ba²⁺][CO₃²⁻] = 0.0273 × 0.124 = 3.4 × 10⁻⁴ > Ksp
Hence, BaCO₃ will precipitate.