whats the mole fraction of urea in a solution prepared by dissolving 16g urea in 39 g h2O?
回答 (2)
2020-05-18 10:32 am
Molar mass of urea = 60 g/mol
Moles of urea = (16 g)/(60 g/mol) = 0.267 mol
Molar mass of H₂O = 18 g/mol
Moles of H₂O = (39 g)/(18 g/mol) = 2.167 mol
Mole fraction of urea = 0.267/(0.267 + 2.167) = 0.11
Moles of urea = (16 g)/(60 g/mol) = 0.267 mol
Molar mass of H₂O = 18 g/mol
Moles of H₂O = (39 g)/(18 g/mol) = 2.167 mol
Mole fraction of urea = 0.267/(0.267 + 2.167) = 0.11
2020-05-18 10:34 am
(16 g urea) / (60 g/mol) = 0.2667 mol
(39 g H2O) / (18.01532 g H2O/mol) = 2.165 mol H2O
( 0.2667 mol urea) / ( 0.2667 mol + 2.165 mol) = 0.1097 =
0.11 (the mole fraction of urea)
(39 g H2O) / (18.01532 g H2O/mol) = 2.165 mol H2O
( 0.2667 mol urea) / ( 0.2667 mol + 2.165 mol) = 0.1097 =
0.11 (the mole fraction of urea)
收錄日期: 2021-04-24 07:56:38
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