What is the approximate enthalpy change for the formation of 3.10 mol of water? 2 H2(g) + O2(g) 2 H2O(l) ΔH = +571.6 kJ?
回答 (1)
2020-05-18 10:40 am
2H₂(g) + O₂(g) → 2H₂O(l) ΔH = +571.6 kJ
When 2 moles of water is formed, enthalpy change = +571.6 kJ
When 3.10 mol of water is formed, enthalpy change
= (+571.6 kJ) × (3.10/2)
= 886 kJ
When 2 moles of water is formed, enthalpy change = +571.6 kJ
When 3.10 mol of water is formed, enthalpy change
= (+571.6 kJ) × (3.10/2)
= 886 kJ
收錄日期: 2021-04-12 12:51:22
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