In a second-order reaction, 2A --> B, the rate constant was found to be 12 L mol–1 min–1
. If the initial concentration of A was 0.55 mol L–1, what was the concentration of A after 75 min?
a. 1.1 x 10–3 mol L–1
b. 5.0 x 10–1 mol L–1
c. 1.9 x 10–5 mol L–1
d. 9.0 x 102 mol L–1
Second-order reaction. chem help?
2020-05-17 7:54 pm
回答 (1)
2020-05-17 11:10 pm
✔ 最佳答案
The integrated rate equation for second-order reaction:1/[A] = kt + (1/[A]ₒ)
1/[A] = 12 × 75 + (1/12)
1/[A] = 900 mol⁻¹ L
[A] = 1.1 × 10⁻³ mol L⁻¹
The answer: a. 1.1 × 10⁻³ mol L⁻¹
收錄日期: 2021-04-12 12:50:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200517115430AAPgSRl