What is the molar it y if a solution containing 85.3 g of silver perchlorate dissolved in 927 g of benzene?

Molar mass of AgClO₄ (silver perchlorate) = 107.9 + 35.5 + 16.0×4 = 207.4 g/mol
Moles of AgClO₄ = (85.3 g) / (207.4 g/mol) = 0.4113 mol

Refer to: https://en.wikipedia.org/wiki/Benzene
Density of benzene = 0.8765 g/mL = 876.5 g/L
Volume of benzene = (927 g) / (876.5 g/L) = 1.058 L

Assume that the volume is unchanged on solubilizing.
Molarity = (0.4113 mol) / (1.058 L) = 0.389 mol/L

Are you sure the question asks for molarity and not molality?

Molarity of the solution is impossible to calculate without making a risky assumption. Since molarity is calculated as moles of solute/L of solution, you have to assume that the volume of the benzene does not change on dissolving this mass of AgClO4. 

You also need to know the density of the benzene, but since density is temperature dependent and you didn't provide a temperature, I can only use the density of benzene that I find.I found the density of benzene at 20C to be 0.879 g/mL. So, the volume of benzene is:927 g / 0.879 g/mL = 1054 mL or 1.054 LMoles AgClO4 = 85.3 g / 207.3 g/mol = 0.410 mol

Molarity = 0.410 mol / 1.054 L = 0.389 M

Now, if you had asked for the molality of the solution:
molality = moles solute / kg solvent
molality = 0.410 mol/ 0.927 kg  = 0.442 molal solution

Molarity  =  moles of solute / Liters of solution
   .....  NOT L of solvent
you can estimate .. but not calc. exactly
  1.  find molar mass of silver perchlorate
  2.  divide  ..  85.3 / molar mass  =  moles AgClO4
  3.  find the density of benzene ..  ??  I don't know this
  4.  927 / density  =  volume in mL
  5.  vol in ml / 1000  =  vol. in L
  6.  moles (step 2) / Liters (step 5)  =  molarity  << answer
=======================================
 maybe you really wanted molality???
  ...  molality = moles f solute / kg of solvent
  1. same as above
  2.  same as above
  3.  927g / 1000g/kg  =  0.927kg solvent
  4.  moles (step 2) / kg (step 3) = molality  <<< answer
======================================
so which did you really want?