If the pH = 5.47, calculate the hydronium ion concentration ?
回答 (2)
2020-05-16 11:24 pm
pH = -log[H₃O⁺] = 5.47
[H₃O⁺] = 10⁻⁵˙⁴⁷ M = 3.39 × 10⁻⁶ M
[H₃O⁺] = 10⁻⁵˙⁴⁷ M = 3.39 × 10⁻⁶ M
2020-05-16 11:30 pm
pH = -log(10){H^+]
Inverting
[H^+] = 10^(-pH)
Hence
[H^+] = 10^(-5.47)
[H^+] = 3.386 x 10^-6 ( = 0.000003386)
Inverting
[H^+] = 10^(-pH)
Hence
[H^+] = 10^(-5.47)
[H^+] = 3.386 x 10^-6 ( = 0.000003386)
收錄日期: 2021-04-18 18:31:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200516151743AAKJbDX