An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 6500 rev/min
The ratio of magnitude of centripetal acceleration to acceleration due to gravity is
what is the ratio of magnitude of centripetal accel. to accel. due to gravity? of. a wheel w/ 7.5 cm and rotates at 6500 rev/min?
2020-05-14 12:40 pm
回答 (3)
2020-05-14 2:05 pm
ω = 6500rev/min * 2π rad/rev * 1min/60s = 13,000π/60 = 650π/3 = 681rad/s
V = ωr -----> V²/r = ω²r = 34,750
34750/9.8 = 3546
V = ωr -----> V²/r = ω²r = 34,750
34750/9.8 = 3546
2020-05-14 1:56 pm
a/g = w^2 R / g = (2*pi() * 6500/60)^2 * 0.075 / 9.8 ~= 3.5 * 10^3
2020-05-14 3:21 pm
Ca = ω^2*r = (0,10472*6500)^2*7.5/100 = 34,750 m/sec^2
Ca/g = 34,750 / 9.807 = 3,540
Ca/g = 34,750 / 9.807 = 3,540
收錄日期: 2021-04-24 07:53:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200514044043AA3uZZY